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Proof step 9 from proof mod2-2pot-01 (previous step)

j0 < 2, 0 ≤ i, 0 ≤ j0, 0 ≤ i0 ⊦ ((i0 * 2 + j0) % (2 ^ i * 2)) / 2 = i0 % 2 ^ i, j0 = 0

Heuristic simplifier applied rule simplifier

And obtained the following new goals

Proof step 10:
0 ≤ i0, 0 ≤ i ⊦ ((i0 * 2 + 1) % (2 ^ i * 2)) / 2 = i0 % 2 ^ i

Rule argument

Additional information

Used simplifier rules: ⊦ i ≤ 0 ∧ 0 ≤ j → i ≤ j; (s)%forward-le-05: ⊦ i < j ∧ 0 ≤ i → 0 < j; (forward) from specification int-abs%forward-le-01: ⊦ i ≤ j ∧ 0 ≤ i → 0 ≤ j; (forward) from specification int-abs% ⊦ 0 < j → (j < 2 ↔ j = 1); (s)% ⊦ i ≠ j → (i ≤ j ↔ i < j); (s)