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Proof step 2 from proof mod2-2pot-02 (previous step)

j % 2 ^ i = 1, 0 < i, 0 ≤ j ⊦ j % 2 = 1

Heuristic simplifier applied rule simplifier

And obtained the following new goals

Proof step 3:
j % 2 ^ i = 1, 0 < i, 0 ≤ j ⊦ j % 2 = 1

Rule argument

Additional information

Used simplifier rules: ⊦ ~1 < i ↔ 0 ≤ i; (s)% ⊦ 1 ≤ i ↔ 0 < i; (s)%numlef-01: ⊦ (* i) ≤ j → i - 1 < j; (forward) from specification int-abs%numlsf-02: ⊦ (* i) < j → i + 1 ≤ j; (forward) from specification int-abs