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Proof step 3 from proof mod2-pos (previous step)

j % 2 ^ i < 0, j % 2 ^ i < j, j % 2 ^ i < i, 0 ≤ j, 0 ≤ i ⊦

User applied rule insert rewrite lemma

And obtained the following new goals

Proof step 4:
⊦ 0 < j ∧ 0 ≤ i → ¬ i % j < 0

Rule argument

spec: int-div name: mod-zero-01 seq: ⊦ 0 < j ∧ 0 ≤ i → ¬ i % j < 0 subst: [j, i] → [2 ^ i, j] flags: <all paths>

Additional information

Used simplifier rules: grz: ⊦ 0 < i → (0 < i ^ j ↔ i = 1 ∨ 0 ≤ j); Used terms: 2 ^ i, j