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Proof step 3 from proof pot-div (previous step)

0 < i, j0 ≤ j, 0 ≤ j, 0 ≤ j0 ⊦ i ^ j / i ^ j0 = i ^ (j - j0)

Heuristic elimination applied rule insert elim lemma

And obtained the following new goals

Proof step 4:
j = i0 + j0, 0 < i, 0 ≤ j0, 0 ≤ j, j0 ≤ j ⊦ i ^ j / i ^ j0 = i ^ i0

Rule argument

spec: int-abs name: elim-sub seq: ⊦ i0 = i - j ↔ i = i0 + j subst: [i, j, i0] → [j, j0, i0]

Additional information

Used simplifier rules: ⊦ i0 = i - j ↔ i = i0 + j; (elim) Used terms: j, j0, i0