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Proof step 3 from proof pot-square-02 (previous step)

0 ≤ j ⊦ (i * i) ^ j = i ^ (2 * j)

User applied rule insert rewrite lemma

And obtained the following new goals

Proof step 4:
⊦ 0 ≤ j ∧ 0 ≤ j0 → i ^ (j * j0) = (i ^ j) ^ j0
Proof step 5:
0 ≤ 2, 0 ≤ j ⊦ (i * i) ^ j = (i ^ 2) ^ j

Rule argument

spec: <toplevel> name: pot-pot-02 seq: ⊦ 0 ≤ j ∧ 0 ≤ j0 → i ^ (j * j0) = (i ^ j) ^ j0 subst: [j0, j, i] → [j, 2, i] flags: <all paths>

Additional information

Used terms: j, 2, i