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Proof step 6 from proof pot-zero-01 (previous step)

i ^ j = 0, 0 < i, 0 ≤ j ⊦

User applied rule insert lemma

And obtained the following new goals

Proof step 7:
⊦ 0 < i → (0 < i ^ j ↔ i = 1 ∨ 0 ≤ j)

Rule argument

spec: <toplevel> name: grz seq: ⊦ 0 < i → (0 < i ^ j ↔ i = 1 ∨ 0 ≤ j) subst: [i, j] → [i, j]

Additional information

Used simplifier rules: ⊦ i ≤ 0 ∧ 0 ≤ j → i ≤ j; (s)%forward-le-05: ⊦ i < j ∧ 0 ≤ i → 0 < j; (forward) from specification int-abs%forward-lsle: ⊦ i < j ∧ j ≤ j0 → i < j0; (forward) from specification int-abs Used terms: i, j