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Proof step 45 from proof pot2-est-div6 (previous step)

0 < (5 + i1) * 6 + j0, ((2 ^ (i1 - 1) * 2) * 2) * 2 < 6 + i1, 0 < i1, 4 * ((2 ^ (i1 - 1) * 2) * 2) * 2 ≤ 3 * (6 + i1), 8 * ((2 ^ (i1 - 1) * 2) * 2) * 2 ≤ (5 + i1) * 6 + j0 + 1, 36 ≤ (5 + i1) * 6 + j0, 0 ≤ j0, 8 * ((2 ^ (i1 - 1) * 2) * 2) * 2 ≤ 6 * (6 + i1), j0 ≤ 5, 0 ≤ (5 + i1) * 6 + j0, 0 ≤ i1 ⊦

Heuristic elimination applied rule insert elim lemma

And obtained the following new goals

Proof step 46:
i1 = i0 + 1, 0 < i1, ((2 ^ i0 * 2) * 2) * 2 < 6 + i1, 0 < (5 + i1) * 6 + j0, 0 ≤ i1, 0 ≤ (5 + i1) * 6 + j0, j0 ≤ 5, 8 * ((2 ^ i0 * 2) * 2) * 2 ≤ 6 * (6 + i1), 0 ≤ j0, 36 ≤ (5 + i1) * 6 + j0, 8 * ((2 ^ i0 * 2) * 2) * 2 ≤ (5 + i1) * 6 + j0 + 1, 4 * ((2 ^ i0 * 2) * 2) * 2 ≤ 3 * (6 + i1) ⊦

Rule argument

spec: int-abs name: elim-sub seq: ⊦ i0 = i - j ↔ i = i0 + j subst: [i, j, i0] → [i1, 1, i]

Additional information

Used simplifier rules: ⊦ i0 = i - j ↔ i = i0 + j; (elim) Used terms: i1, 1, i