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Proof step 5 from proof pot2-ls-pred-01 (previous step)

2 ^ (i - 1) + 1 < 2 ^ i, i ≤ 0 ⊦

User applied rule insert rewrite lemma

And obtained the following new goals

Proof step 6:
⊦ i < 0 → j ^ i = 1 / j ^ abs(i)
Proof step 7:
2 ^ (i - 1) + 1 < 1 / 2 ^ abs(i), i < 0, i ≤ 0 ⊦

Rule argument

spec: <toplevel> name: Pot-neg seq: ⊦ i < 0 → j ^ i = 1 / j ^ abs(i) subst: [i, j] → [i, 2] flags: <all paths>

Additional information

Used simplifier rules: ⊦ i < j ↔ ¬ j ≤ i; (ss)% ⊦ i ≤ j → (j ≤ i ↔ i = j); (s) Used terms: i, 2