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Proof step 2 from proof pot2-pos-04 (previous step)

i < 0 ⊦ 2 * i ≤ 2 ^ j + 1

Heuristic simplifier applied rule simplifier

And obtained the following new goals

Proof step 3:
2 ^ j + 1 < 2 * i, i < 0 ⊦

Rule argument

Additional information

Used simplifier rules: forward-le-02: ⊦ j < i ∧ i ≤ 0 → j < 0; (forward) from specification int-abs% ⊦ i ≤ j ↔ ¬ j < i; (ss)