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Proof step 2 from proof two-le-01 (previous step)

0 ≤ i ⊦ 2 ^ i ≤ 2 ↔ i ≤ 1

User applied rule insert lemma

And obtained the following new goals

Proof step 3:
⊦ 0 ≤ i → (2 ^ i ≤ 2 ^ j ↔ i ≤ j)

Rule argument

spec: <toplevel> name: two-le seq: ⊦ 0 ≤ i → (2 ^ i ≤ 2 ^ j ↔ i ≤ j) subst: [i, j] → [i, 1]

Additional information

Used terms: i, 1