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Proof step 3 from proof two-le (
previous step
)
0 ≤ i ⊦ 2 ^ i ≤ 2 ^ j ↔ i ≤ j
User applied rule insert rewrite lemma
And obtained the following new goals
Proof step 4
:
⊦ 1 < i ∧ 0 ≤ j → (i ^ j ≤ i ^ j0 ↔ j ≤ j0)
Rule argument
spec: <toplevel> name: le-pos seq: ⊦ 1 < i ∧ 0 ≤ j → (i ^ j ≤ i ^ j0 ↔ j ≤ j0) subst: [j0, j, i] → [j, i, 2] flags: <all paths>
Additional information
Used terms: j, i, 2