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Proof step 5 from proof two-mod-01 (previous step)

1 < i, 0 < i, 2 ≤ i ⊦ (2 ^ i -1 * 2 - 1) % 2 = 1

User applied rule insert rewrite lemma

And obtained the following new goals

Proof step 6:
⊦ 0 < i → (i * 2 - 1) % 2 = 1

Rule argument

spec: int-div name: mod-two-03 seq: ⊦ 0 < i → (i * 2 - 1) % 2 = 1 subst: [i] → [2 ^ i -1] flags: <all paths>

Additional information

Used simplifier rules: two-mone: ⊦ 1 < i → ¬ 2 ^ i -1 ≤ 0;% ⊦ i < j ↔ ¬ j ≤ i; (ss) Used terms: 2 ^ i -1