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Proof step 9 from proof even (previous step)

((2 * i0) * (2 * i0 + 1) + 1 * (2 * i0 + 1)) % 2 = 0 ⊦

User applied rule insert rewrite lemma

And obtained the following new goals

Rule argument

spec: int-mult name: one seq: ⊦ 1 * i = i subst: [i] → [2 * i0 + 1] flags: <all paths>

Additional information

Used terms: 2 * i0 + 1