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Proof step 3 from proof root-abs (
previous step
)
sqrt(i) < 0, sqrt(i) < i, 0 ≤ i ⊦
User applied rule insert lemma
And obtained the following new goals
Proof step 4
:
⊦ 0 ≤ i → 0 ≤ sqrt(i)
Rule argument
spec: <toplevel> name: root-pos seq: ⊦ 0 ≤ i → 0 ≤ sqrt(i) subst: [i] → [i]
Additional information
Used simplifier rules: ⊦ i < j → (j ≤ i ↔ false); (as) Used terms: i