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Proof step 5 from proof square-le-one (previous step)

i < 4, 0 < i, 0 < sqrt(i), 1 < sqrt(i) ⊦

User applied rule insert rewrite lemma

And obtained the following new goals

Proof step 6:
⊦ i ≠ j -1 → (i < j ↔ i < j -1)
Proof step 7:
i = 4 -1, 1 < sqrt(i), 0 < sqrt(i), 0 < i, i < 4 ⊦
Proof step 8:
1 < sqrt(i), 0 < sqrt(i), 0 < i, i < 4 -1 ⊦ i = 4 -1

Rule argument

spec: int-basic1 name: ls-rec seq: ⊦ i ≠ j -1 → (i < j ↔ i < j -1) subst: [j, i] → [4, i] flags: <all paths>

Additional information

Used terms: 4, i