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Proof step 3 from proof square-not-neg-02 (previous step)

sqrt(i) < i, 0 < i, sqrt(i) ≤ 0 ⊦ i = 0

User applied rule insert lemma

And obtained the following new goals

Proof step 4:
⊦ 0 ≤ i → 0 ≤ sqrt(i)
Proof step 5:
0 < i, sqrt(i) < i, sqrt(i) ≤ 0, 0 ≤ i → 0 ≤ sqrt(i) ⊦ i = 0

Rule argument

spec: <toplevel> name: root-pos seq: ⊦ 0 ≤ i → 0 ≤ sqrt(i) subst: [i] → [i]

Additional information

Used terms: i