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Proof step 1 from proof square-two (conclusion)

⊦ sqrt(2) = 1

User applied rule insert lemma

And obtained the following new goals

Proof step 2:
⊦ 0 ≤ i → sqrt(i) ^2 ≤ i ∧ i < sqrt(i) +1 ^2
Proof step 3:
0 ≤ 2 → sqrt(2) ^2 ≤ 2 ∧ 2 < sqrt(2) +1 ^2 ⊦ sqrt(2) = 1

Rule argument

spec: <toplevel> name: Sqrt-def seq: ⊦ 0 ≤ i → sqrt(i) ^2 ≤ i ∧ i < sqrt(i) +1 ^2 subst: [i] → [2]

Additional information

Used terms: 2