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Proof step 7 from proof two-even-01 (previous step)

(j1 + j2) % 2 = 0, 2 * (j1 ^2 + j2 ^2) / 2 = j1 ^2 + j2 ^2 → (j1 ^2 + j2 ^2) / 2 = ((j1 - j2) / 2)^2 + ((j1 + j2) / 2)^2 ⊦ j1 ^2 + j2 ^2 = 2 * (((j1 - j2) / 2)^2 + ((j1 + j2) / 2)^2), 2 ≠ 0 ∧ (j1 ^2 + j2 ^2) % 2 = 0

Heuristic simplifier applied rule simplifier

And closed the goal!

Rule argument

Additional information

Used simplifier rules: add-even: ⊦ (j1 + j2) % 2 = 0 → ((j1 ^2 + j2 ^2) % 2 = 0 ↔ true);%add-c: ⊦ i + j = j + i; from specification int-basic2%add-a: ⊦ i + j + i0 = (i + j) + i0; from specification int-basic2