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Proof step 5 from proof two-le-three (previous step)

1 < abs(i), i * i ≤ 3 ⊦ i = 0

User applied rule cut formula

And obtained the following new goals

Proof step 6:
1 < abs(i), i * i < 2 * 2, i * i ≤ 3 ⊦ i = 0

Rule argument

fma: i * i < 2 * 2

Additional information

Used simplifier rules: j0 ≠ 0, j < j0 ⊦ i ≤ (* j) → i < (* j0); (s) Used formulas: i * i < 2 * 2