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Proof step 1 from proof two-pm (conclusion)

⊦ (i * i0 + j * j0)^2 = i ^2 * i0 ^2 + 2 * i * i0 * j * j0 + j ^2 * j0 ^2

User applied rule insert rewrite lemma

And obtained the following new goals

Proof step 2:
⊦ (i + j)^2 = i ^2 + 2 * i * j + j ^2
Proof step 3:
⊦ (i * i0)^2 + 2 * (i * i0) * j * j0 + (j * j0)^2 = i ^2 * i0 ^2 + 2 * i * i0 * j * j0 + j ^2 * j0 ^2

Rule argument

spec: <toplevel> name: two-plus seq: ⊦ (i + j)^2 = i ^2 + 2 * i * j + j ^2 subst: [j, i] → [j * j0, i * i0] flags: <all paths>

Additional information

Used terms: j * j0, i * i0