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Proof step 2 from proof abs-pred-01 (previous step)

i < 0 ⊦ i = ~1, i→n(i + 1) = i→n(i) -1

Heuristic simplifier applied rule simplifier

And obtained the following new goals

Proof step 3:
i < 0 ⊦ i = ~1, i→n(i + 1) = i→n(i) - 1

Rule argument

Additional information

Used simplifier rules: ⊦ n -1 = n - 1; (s)