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Proof step 3 from proof abs-succ-01 (previous step)

i < 0 ⊦ i→n(i + 1) < i→n(i)

Heuristic simplifier applied rule simplifier

And obtained the following new goals

Proof step 4:
i < 0, i→n(i) ≤ i→n(i + 1) ⊦

Rule argument

Additional information

Used simplifier rules: forward-le-02: ⊦ j < i ∧ i ≤ 0 → j < 0; (forward) from specification int-abs% ⊦ m < n ↔ ¬ n ≤ m; (ss)