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Proof step 13 from proof i2n-mod (previous step)

j0 < j, 0 < j, 0 ≤ j, 0 ≤ j0, 0 ≤ i0 ⊦ i→n(j0) = i→n(j0) % i→n(j), i→n(j0) < i→n(j)

Heuristic simplifier applied rule simplifier

And obtained the following new goals

Proof step 14:
0 < j, j0 < j, 0 ≤ i0, 0 ≤ j0, 0 ≤ j, i→n(j) ≤ i→n(j0) ⊦ i→n(j0) = i→n(j0) % i→n(j)

Rule argument

Additional information

Used simplifier rules: ⊦ m < n ↔ ¬ n ≤ m; (ss)