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Proof step 3 from proof inni-le (previous step)

n→i(n) < i, 0 < i, i→n(i) ≤ n ⊦

User applied rule insert rewrite lemma

And obtained the following new goals

Proof step 4:
⊦ i→n(i) ≤ n ↔ abs(i) ≤ n→i(n)

Rule argument

spec: <toplevel> name: switch-le seq: ⊦ i→n(i) ≤ n ↔ abs(i) ≤ n→i(n) subst: [n, i] → [n, i] flags: <all paths>

Additional information

Used simplifier rules: ⊦ 0 < j → abs(j) = j; (s)% ⊦ i < j → (j ≤ i ↔ false); (as) Used terms: n, i