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Proof step 2 from proof le-fin-add (previous step)

n→i(m) ≤ n→i(n) + i, 0 ≤ i ⊦ m ≤ n + i→n(i)

Heuristic simplifier applied rule simplifier

And obtained the following new goals

Proof step 3:
n + i→n(i) < m, n→i(m) ≤ n→i(n) + i, 0 ≤ i ⊦

Rule argument

Additional information

Used simplifier rules: ⊦ m < n → n ≠ 0; (s)%forward-le-01: ⊦ i ≤ j ∧ 0 ≤ i → 0 ≤ j; (forward) from specification int-abs%f: ⊦ m < n → n ≠ 0; (forward) from specification nat-basic% ⊦ m ≤ n ↔ ¬ n < m; (ss)