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Proof step 2 from proof ls-fin-add (previous step)

n→i(m) < n→i(n) + i, 0 ≤ i ⊦ m < n + i→n(i)

Heuristic simplifier applied rule simplifier

And obtained the following new goals

Proof step 3:
n→i(m) < n→i(n) + i, 0 < n→i(n) + i, n + i→n(i) ≤ m, 0 ≤ i ⊦

Rule argument

Additional information

Used simplifier rules: pos-int: ⊦ n→i(m) < j → 0 < j;%forward-le-01: ⊦ i ≤ j ∧ 0 ≤ i → 0 ≤ j; (forward) from specification int-abs% ⊦ m < n ↔ ¬ n ≤ m; (ss)