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Proof step 4 from proof ls-int-ls-nat (previous step)

i + n→i(n) < n→i(m), 0 ≤ i ⊦ i→n(i) + n < m

Heuristic simplifier applied rule simplifier

And obtained the following new goals

Proof step 5:
i + n→i(n) < n→i(m), 0 ≤ i, m ≤ i→n(i) + n ⊦

Rule argument

Additional information

Used simplifier rules: ⊦ m < n ↔ ¬ n ≤ m; (ss)