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Proof step 2 from proof mult-ls-05 (previous step)

i0 < i / (n→i(n) + 1) ⊦ i0 * n→i(n) + i0 < i

Heuristic simplifier applied rule simplifier

And obtained the following new goals

Proof step 3:
i0 < i / (n→i(n) + 1), i ≤ i0 * (n→i(n) + 1) ⊦

Rule argument

Additional information

Used simplifier rules: ⊦ i < j ↔ ¬ j ≤ i; (ss)%add-c: ⊦ i + j = j + i; from specification int-basic2%add-a: ⊦ i + j + i0 = (i + j) + i0; from specification int-basic2%commutativity: ⊦ i * j = j * i; from specification int-mult%associativity: ⊦ i * j * j0 = (i * j) * j0; from specification int-mult% ⊦ i * j + i = i * (j + 1); (s)