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Proof step 1 from proof n2i2 (conclusion)

⊦ n→i(m) = 1 + 1 ↔ m = 2

User applied rule structural induction

And closed the goal!

Rule argument

indvar: m

Additional information

Used simplifier rules: num-n2i-eq: 0 ≤ i ⊦ n→i(n) = (* i) ↔ n = i→n(i);%n2i-add: ⊦ n→i(m + n) = n→i(m) + n→i(n);%nat freely generated by 0, +1;;%add-a: ⊦ i + j + i0 = (i + j) + i0; from specification int-basic2%add-c: ⊦ i + j = j + i; from specification int-basic2% ⊦ m +1 = m + 1; (s)%a: ⊦ (m + n0) + n1 = m + n0 + n1; from specification nat-basic%c: ⊦ m + n = n + m; from specification nat-basic% ⊦ (* j) = i0 + (* j0) ↔ j - j0 = i0; (s)%n0 < n ⊦ (* n) = m0 + (* n0) ↔ n - n0 = m0; (s)