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Proof step 2 from proof nat (previous step)

⊦ i→n(i) / i→n(j) = i→n(i / j), j = 0

User applied rule cut formula

And obtained the following new goals

Proof step 3:
i < 0 ⊦ i→n(i) / i→n(j) = i→n(i / j), j = 0
Proof step 8:
⊦ i→n(i) / i→n(j) = i→n(i / j), j = 0, i < 0

Rule argument

fma: i < 0

Additional information

Used formulas: i < 0