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Proof step 2 from proof qzero-01 (previous step)

i < j ⊦ n→i(n) * (i - j) ≤ 0

Heuristic simplifier applied rule simplifier

And obtained the following new goals

Proof step 3:
i < j, 0 < n→i(n) * (i - j) ⊦

Rule argument

Additional information

Used simplifier rules: ⊦ 1 ≤ i ↔ 0 < i; (s)%numlsf-02: ⊦ (* i) < j → i + 1 ≤ j; (forward) from specification int-abs% ⊦ i ≤ j ↔ ¬ j < i; (ss)