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Proof step 1 from proof two-01 (conclusion)

⊦ i→n(1 + 1) = 2

User applied rule insert rewrite lemma

And obtained the following new goals

Rule argument

spec: <toplevel> name: rax-04 seq: ⊦ 0 ≤ i → i→n(i + 1) = i→n(i) + 1 subst: [i] → [1] flags: <all paths>

Additional information

Used terms: 1