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Proof step 2 from proof elim-list-c (previous step)

⊦ a = x.head ∧ y = x.tail ↔ x = a + y, x = []

Heuristic simplifier applied rule simplifier

And obtained the following new goals

Proof step 3:
⊦ x = x.head + x.tail, x = []

Rule argument

Additional information

Used simplifier rules: sel-1: ⊦ (a + x).head = a;%sel-2: ⊦ (a + x).tail = x;