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Proof step 2 from proof elim-list (previous step)

⊦ a = x.head ∧ y = x.tail ↔ x = a + y, x = []

Heuristic simplifier applied rule simplifier

And closed the goal!

Rule argument

Additional information

Used simplifier rules: fr-02: ⊦ x ≠ [] → x.head + x.tail = x;%sel-1: ⊦ (a + x).head = a;%sel-2: ⊦ (a + x).tail = x;