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Proof step 2 from proof le-one (previous step)

# x ≤ 1 ⊦ # x = 1, x = []

Heuristic simplifier applied rule simplifier

And closed the goal!

Rule argument

Additional information

Used simplifier rules: l: ⊦ # x = 0 ↔ x = [];% ⊦ m < 1 ↔ m = 0; (s)% ⊦ m ≠ n → (m ≤ n ↔ m < n); (s)