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Proof step 3 from proof lr-03 (previous step)

⊦ # x.tail = # y.tail ↔ # x = # y, x = [], y = []

Heuristic elimination applied rule insert elim lemma

And obtained the following new goals

Proof step 4:
x ≠ [] ⊦ a = x.head ∧ y = x.tail ↔ x = a + y
Proof step 5:
x = a + y0 ⊦ # y0 = # y.tail ↔ # x = # y, x = [], y = []

Rule argument

spec: <toplevel> name: elim-list-c seq: x ≠ [] ⊦ a = x.head ∧ y = x.tail ↔ x = a + y subst: [x, a, y] → [x, a, y0] flags: <rotated> <all paths>

Additional information

Used terms: x, a, y0