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Proof step 13 from proof blastN-firstN (previous step)

n ≤ # x0, ∀ n. n ≤ # x0 → butlastn(n, x0) = firstn(# x0 - n, x0) ⊦ a ' + butlastn(n, x0) = a ' + firstn(# x0 - n, x0), 1 + # x0 = n

Heuristic simplifier applied rule simplifier

And obtained the following new goals

Proof step 14:
n ≤ # x0, ∀ n. n ≤ # x0 → butlastn(n, x0) = firstn(# x0 - n, x0) ⊦ 1 + # x0 = n, butlastn(n, x0) = firstn(# x0 - n, x0)

Rule argument

Additional information

Used simplifier rules: a: ⊦ (x + y) + z = x + y + z; from specification list% ⊦ x + y = x + z ↔ y = z; (s)