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Proof step 6 from proof del-append (previous step)

∀ y, a. (x0 + y) -l a = (x0 -l a) + (y -l a) ⊦ ((a0 ' + x0) + y) -l a = ((a0 ' + x0) -l a) + (y -l a), a = a0

Heuristic simplifier applied rule simplifier

And obtained the following new goals

Proof step 7:
∀ y, a. (x0 + y) -l a = (x0 -l a) + (y -l a) ⊦ (x0 + y) -l a = (x0 -l a) + (y -l a), a = a0

Rule argument

Additional information

Used simplifier rules: del-n: ⊦ a ≠ b → (b ' + x) -l a = b ' + (x -l a);% ⊦ x + y = x + z ↔ y = z; (s)%a: ⊦ (x + y) + z = x + y + z; from specification list