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Proof step 14 from proof del-rev (previous step)

∀ a. rev(x0) -l a = rev(x0 -l a) ⊦ (rev(x0) -l a) + a0 ' = rev(x0 -l a) + a0 ', a = a0, a ∈ a0 '

Heuristic simplifier applied rule simplifier

And obtained the following new goals

Proof step 15:
∀ a. rev(x0) -l a = rev(x0 -l a) ⊦ rev(x0) -l a = rev(x0 -l a), a = a0

Rule argument

Additional information

Used simplifier rules: ⊦ a ∈ b ' ↔ a = b; (s)%a: ⊦ (x + y) + z = x + y + z; from specification list% ⊦ x + y = z + y ↔ x = z; (s)