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Proof step 1 from proof delnr-one (conclusion)

⊦ a ' -p 0 = []

User applied rule apply lemma

And obtained the following new goals

Proof step 2:
⊦ (a ' + x) -p 0 = x

Rule argument

spec: <toplevel> name: delpos-base seq: ⊦ (a ' + x) -p 0 = x subst: [a, x] → [a, []]

Additional information

Used simplifier rules: ⊦ x + [] = x; (s)%a: ⊦ (x + y) + z = x + y + z; from specification list Used terms: a, []