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Proof step 1 from proof first-mklist-04 (conclusion)

⊦ firstn(m, mklist(a, m)) = mklist(a, m)

User applied rule insert rewrite lemma

And obtained the following new goals

Proof step 2:
⊦ # x = n → firstn(n, x) = x

Rule argument

spec: <toplevel> name: first-all-01 seq: ⊦ # x = n → firstn(n, x) = x subst: [x, n] → [mklist(a, m), m] flags: <all paths>

Additional information

Used simplifier rules: ⊦ # mklist(a, n) = n; (s) Used terms: mklist(a, m), m