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Proof step 11 from proof first-mklist (previous step)

m ≤ n0 + 1, ∀ m, a. m ≤ n0 → firstn(m, mklist(a, n0)) = mklist(a, m) ⊦ a ' + firstn(m - 1, mklist(a, n0)) = mklist(a, m), m = 0

Heuristic elimination applied rule insert elim lemma

And obtained the following new goals

Proof step 12:
m = m0 + 1, m ≤ n0 + 1, ∀ m, a. m ≤ n0 → firstn(m, mklist(a, n0)) = mklist(a, m) ⊦ a ' + firstn(m0, mklist(a, n0)) = mklist(a, m), m = 0

Rule argument

spec: nat name: elim-pred-c seq: n ≠ 0 ⊦ m = n - 1 ↔ n = m + 1 subst: [n, m] → [m, m0]

Additional information

Used simplifier rules: n ≠ 0 ⊦ m = n - 1 ↔ n = m + 1; (elim) Used terms: m, m0