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Proof step 3 from proof firstN-dups-01 (previous step)

n < # y, dups(x + firstn(n, y)) ⊦ y = [], dups(y), dups(x), dups(x + y)

User applied rule insert rewrite lemma

And obtained the following new goals

Rule argument

spec: <toplevel> name: firstN-dups-03 seq: ⊦ n ≤ # y ∧ ¬ dups(x + y) → ¬ dups(x + firstn(n, y)) subst: [y, n, x] → [y, n, x] flags: <all paths>

Additional information

Used simplifier rules: ⊦ m ≤ n ↔ ¬ n < m; (ss)% ⊦ m < n → ¬ n < m; (s) Used terms: y, n, x