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Proof step 2 from proof firstN-dups-03 (previous step)

dups(x + firstn(n, y)), n ≤ # y ⊦ dups(x + y)

Heuristic simplifier applied rule simplifier

And obtained the following new goals

Rule argument

Additional information

Used simplifier rules: a: ⊦ (x + y) + z = x + y + z; from specification list%a: ⊦ ¬ dups(x + y) → ¬ dups(x) ∧ ¬ dups(y); (forward) from specification list-dup