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Proof step 3 from proof firstN-dups (previous step)

n < # x, dups(firstn(n, x) + y) ⊦ x = [], dups(y), dups(x), dups(x + y)

User applied rule insert rewrite lemma

And obtained the following new goals

Rule argument

spec: <toplevel> name: firstN-dups-02 seq: ⊦ n ≤ # x ∧ ¬ dups(x + y) → ¬ dups(firstn(n, x) + y) subst: [y, x, n] → [y, x, n] flags: <all paths>

Additional information

Used simplifier rules: ⊦ m ≤ n ↔ ¬ n < m; (ss)% ⊦ m < n → ¬ n < m; (s) Used terms: y, x, n