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Proof step 2 from proof firstn-allprefix (
previous step
)
# x0 = n, x0 ⊑ x2 ⊦ firstn(n, x2) = x0
Heuristic simplifier applied rule simplifier
And obtained the following new goals
Proof step 3
:
x0 ⊑ x2 ⊦ firstn(# x0, x2) = x0
Rule argument
Additional information