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Proof step 3 from proof firstn-first (previous step)

⊦ firstn(n, x).head = x.head, n = 0, x = []

Heuristic elimination applied rule insert elim lemma

And obtained the following new goals

Proof step 4:
x = a + y ⊦ firstn(n, x).head = a, n = 0, x = []

Rule argument

spec: list-data name: elim-list-c seq: x ≠ [] ⊦ a = x.head ∧ y = x.tail ↔ x = a + y subst: [x, a, y] → [x, a, y]

Additional information

Used simplifier rules: x ≠ [] ⊦ a = x.head ∧ y = x.tail ↔ x = a + y; (elim) Used terms: x, a, y