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Proof step 2 from proof firstn-length-01 (previous step)

x = firstn(n, x) + a ' + z ⊦ # x > # z ↔ true

Heuristic simplifier applied rule simplifier

And obtained the following new goals

Proof step 3:
x = firstn(n, x) + a ' + z, # x ≤ # z ⊦

Rule argument

Additional information

Used simplifier rules: ⊦ m < n ↔ ¬ n ≤ m; (ss)% ⊦ m > n ↔ n < m; (s)