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Proof step 2 from proof get-app (previous step)

∀ a, y. (x0 + a ' + y)[# x0] = a ⊦ ((a0 + x0) + a ' + y)[#(a0 + x0)] = a

Heuristic simplifier applied rule simplifier

And obtained the following new goals

Proof step 3:
∀ a, y. (x0 + a ' + y)[# x0] = a ⊦ (x0 + a ' + y)[# x0] = a

Rule argument

Additional information

Used simplifier rules: get-succ: ⊦ (a ' + x)[n + 1] = x[n];%c: ⊦ m + n = n + m; from specification nat-basic%a: ⊦ (m + n0) + n1 = m + n0 + n1; from specification nat-basic% ⊦ # a ' = 0 +1; (s)% ⊦ #(x + y) = # x + # y; (s)%a: ⊦ (x + y) + z = x + y + z; from specification list% ⊦ a + x = a ' + x; (s)