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Proof step 3 from proof get-butlast (previous step)

n < # x ⊦ (x + a ')[n] = x[n], x = []

Heuristic structural induction applied rule structural induction

And obtained the following new goals

Proof step 4:
n < #(a0 + x0), ∀ n, a. n < # x0 → (x0 + a ')[n] = x0[n] ∨ x0 = [] ⊦ a0 + x0 = [], ((a0 + x0) + a ')[n] = (a0 + x0)[n]

Rule argument

term: x

Additional information

Used simplifier rules: list freely generated by [], +;;